7v^2+2v-20=-4v

Solution for 7v^2+2v-20=-4v equation:

7v^2+2v-20=-4v

We move all terms to the left:

7v^2+2v-20-(-4v)=0

We get rid of parentheses

7v^2+2v+4v-20=0

We add all the numbers together, and all the variables

7v^2+6v-20=0

a = 7; b = 6; c = -20;
Δ = b2-4ac
Δ = 62-4·7·(-20)
Δ = 596
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{596}=\sqrt{4*149}=\sqrt{4}*\sqrt{149}=2\sqrt{149}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{149}}{2*7}=\frac{-6-2\sqrt{149}}{14}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{149}}{2*7}=\frac{-6+2\sqrt{149}}{14}
$